ZOJ 1055 Oh, Those Achin Feet.bfs求最短路径.
ZOJ 1055 Oh, Those Achin Feet.bfs求最短路径.
题意：三维空间，求起点到终点的最短路径，如果没有输出”Trapped!“ 分析： 最短路径问题用bfs. 注意与分块问题的区别：计数器 t 放在node结构体里面；循环里如果a[x][y][z]="end" 返回 t+1;循环外返回 -1 来确定无...
How Many Shortest Path Time Limit: 10 Seconds Memory Limit: 32768 KB Given a weighted directed graph, we define the shortest path as the path who has the smallest length among all the pat
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=649 RescueTime Limit:2 Seconds Memory Limit:65536 KB Angel was caught by the MOLIGPY! He was put in prison by Moligpy. The prison...
#include<stdio.h> #include<iostream> #include<memory.h> #include<string.h> #include<string> #include<algorithm> #include<vector> #include<...int v
最短路算法详解（dijkstra/SPFA/floyd） 时间 2014-02-16 13:08:23 程序员宅基地 原文 ... 主题 Dijkstra算法 ...Dijkstra单源最短路算法，即计算从起点出发到每个点的最短路。所以Dijk
How Many Shortest Path Time Limit: 10 Seconds Memory Limit: 32768 KB Given a weighted directed graph, we define the shortest path as the path who has the smallest length among all the pa
Cerror is the mayor of city HangZhou. As you may know, the traffic system of this city is so terrible, that there are traffic jams everywhere. Now, Cerror finds out that the main reason of them is the...
题目大意：字符一样并且相邻的即为连通。每次可翻转一个连通块X(O)的颜色，问至少改变几次使得图上所有字符都...所以，dfs把连通块缩成点，然后相邻的连通块之间建边，枚举以每个点为根的情况，求最短路。 #inclu...
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zoj1005 BFS+路径输出 这道题一开始就想用搜索做，想的实际上也没错，因为要输出路径，所以我一开始使用了dfs。但发现深搜就会沿着一条路走到底，而我们只能判断它是否达到了目标状态。如果它不到达目标状态可能会...
题目链接： ... http://poj.org/problem?id=1130 这两个题只有输入输出形式不一样。ZOJ的麻烦一点，这里用的ZOJ的输入输出方式 解题报告： 1、输入方式sscanf(line,"%d%d",&a,&b);表示在文本line中...
int bfs() { int i; memset(vis, 0, sizeof(vis)); priority_queue<node > q; node now; now.x=0; now.y=0; now.dir=3; now.step=0; now.g=0; q.push(now); vis[now.x][now.y][0]=1; while (!q.empty())...
通过几道经典BFS例题阐述BFS思路 ZOJ2913-Bus Pass 题意：找一个center区域，使得center到所有公交线路最短，有等距的center则输出id最小的。 题解：经典的BFS，由公交线路最多只经过10*20个区域，而...
虽然以前做过最短路径的条数问题，但这个问题有点奇葩，在最短路径数量中，路径不能重复使用= =.... 如果可以重复使用还是很简单的，用dij去推就好了。将起点赋值为1，向相邻的边推自己，如果0->1有两条边同样短，...
题目链接ZOJ链接 Problem Description Angel was caught by the MOLIGPY! He was put in prison by Moligpy. The prison is described as a N * M (N, M <= 200) matrix. There are WALLs, ROADs, and GUARDs i...
被归在最短路径下面，其实完全可以用bfs解决，要说bfs也算是dijkstra的一种特殊情况吧。 这道题的最大的难度不是解决问题的过程，而是读题的过程，题意叙述可够难为人的，英文啊英文。。。 ...
How Many Shortest Path Time Limit: 10 Seconds Memory Limit: 32768 KB ...Given a weighted directed graph, we define the shortest path as the path who has the smallest length among all the
Angel was caught by the MOLIGPY! He was put in prison by Moligpy. The prison is described as a N * M (N, M Angel's friends want to save Angel. Their task is: approach Angel. We assume that "approach
You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south...
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A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that visits each square of a given set of n squares ...
2 BFS+模拟：dp[i][j][p] 表示走到i，j，方向为p的步数为多少； 3 BFS分4种情况入队，最后在终点4个方向寻找最小值:) 4 */ 5 #include <cstdio> 6 #include <iostream> 7 #include <al...
题意： 给出一个N*M的棋盘，每个格子有白色...每次可以选择一大块联通的棋子进行翻转，使整块变成另一种颜色，求最少要操作多少次才能使得整个棋盘的颜色一致 分析： 题中很明显地提到了联通这个概念，我们首先会想到
题目大意：字符一样并且相邻的即为连通。每次可翻转一个连通块X(O)的颜色，问至少改变几次使得图上所有字符都相等。 解题思路： 1) dfs( 建图 ) ,因为翻转的时候每翻转连通块中一个整个连通块都翻转，这样你可以...
BFS 然后上来第一题n皇后 wdnmd，又t了三遍，一看题解nmd打表。。。我佛了、 // // main.cpp // n皇后_复习 // // Created by 陈冉飞 on 2019/8/16. // Copyright © 2019 陈冉飞. All rights reserved. // #...